College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter P - Prerequisites: Fundamental Concepts of Algebra - Exercise Set P.3: 77

Answer

$13\sqrt[3]2$

Work Step by Step

$$5\sqrt[3]{16} + \sqrt[3]{54}$$ $$=5\sqrt[3]{8\times2} + \sqrt[3]{27\times2}$$ $$=(5\times2)\sqrt[3]{2} + 3\sqrt[3]{2}$$ $$=10\sqrt[3]{2} +3\sqrt[3]{2}$$ $$=(10+3)\sqrt[3]{2}$$ $$=13\sqrt[3]{2}$$
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