College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter P - Prerequisites: Fundamental Concepts of Algebra - Exercise Set P.3: 112

Answer

$\frac{2x^{3}}{y}$

Work Step by Step

$(8x^{-6}y^{3})^{\frac{1}{3}}$$(x^{\frac{5}{6}}y^{-\frac{1}{3}})^{6}$ = $(8^{\frac{1}{3}}x^{-6\times\frac{1}{3}}y^{3\times\frac{1}{3}})$$(x^{\frac{5}{6}\times6}y^{-\frac{1}{3}\times6})$ = ($ \sqrt[3] 8x^{-2} y$)($x^{5}y^{-2}$) = ($ 2x^{-2 + 5} y^{1-2}$) = $ 2x^{3} y^{-1}$ = $\frac{2x^{3}}{y}$
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