## College Algebra (6th Edition)

$\frac{2x^{3}}{y}$
$(8x^{-6}y^{3})^{\frac{1}{3}}$$(x^{\frac{5}{6}}y^{-\frac{1}{3}})^{6} = (8^{\frac{1}{3}}x^{-6\times\frac{1}{3}}y^{3\times\frac{1}{3}})$$(x^{\frac{5}{6}\times6}y^{-\frac{1}{3}\times6})$ = ($\sqrt[3] 8x^{-2} y$)($x^{5}y^{-2}$) = ($2x^{-2 + 5} y^{1-2}$) = $2x^{3} y^{-1}$ = $\frac{2x^{3}}{y}$