College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter P - Prerequisites: Fundamental Concepts of Algebra - Exercise Set P.3: 70

Answer

$x\sqrt[3] x^{2}$

Work Step by Step

$\sqrt[3] x^{5}=\sqrt[3] (x^{3}\times x^{2})=\sqrt[3] x^{3}\times\sqrt[3] x^{2}=x\sqrt[3] x^{2}$ We know that $\sqrt[3] x^{3}=x$, because $(x)^{3}=x^{3}$.
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