College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter P - Prerequisites: Fundamental Concepts of Algebra - Exercise Set P.3: 65

Answer

$-\frac{1}{2}$

Work Step by Step

We know that $\sqrt[5] -\frac{1}{32}=-\frac{1}{2}$, because $(-\frac{1}{2})^{5}=-\frac{1}{2}\times-\frac{1}{2}\times-\frac{1}{2}\times-\frac{1}{2}\times-\frac{1}{2}=-\frac{1}{32}$.
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