## College Algebra (6th Edition)

Based on the definition of $a^{\frac{m}{n}}$, we know that $a^{\frac{m}{n}}=\sqrt[n] a^{m}=(\sqrt[n] a)^{m}$ (where $\sqrt[n] a$ represents a real number). Therefore, $\sqrt[5] (-2)^{5}=(-2)^{\frac{5}{5}}=(-2)^{1}=-2$.