College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter P - Prerequisites: Fundamental Concepts of Algebra - Exercise Set P.3: 50

Answer

$\frac{(9 - 3\sqrt 7)}{2}$

Work Step by Step

$\frac{3}{(3 + \sqrt 7)}$ = $\frac{3\times(3 - \sqrt 7)}{(3 + \sqrt 7)\times(3 - \sqrt 7) }$ = $\frac{(9 - 3\sqrt 7)}{(3^{2} - \sqrt 7^{2}) }$ = $\frac{(9 - 3\sqrt 7)}{(9 - 7)}$ = $\frac{(9 - 3\sqrt 7)}{2}$
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