College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter P - Prerequisites: Fundamental Concepts of Algebra - Exercise Set P.3: 49

Answer

$\frac{(13\sqrt 11 - 39)}{2}$

Work Step by Step

$\frac{13}{(3 + \sqrt 11)}$ =$\frac{13\times(3 - \sqrt 11)}{(3 + \sqrt 11)\times(3 - \sqrt 11)}$ =$\frac{(39- 13\sqrt 11)}{3^{2} - \sqrt 11^{2}}$ =$\frac{(39- 13\sqrt 11)}{9 - 11}$ =$\frac{(39- 13\sqrt 11)}{- 2}$ =$\frac{(13\sqrt 11 - 39)}{2}$
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