## College Algebra (6th Edition)

$\sqrt 6$ + 12 $\sqrt 7$
3$\sqrt 54$ - 2 $\sqrt 24$ - $\sqrt 96$ + 4$\sqrt 63$ =3$\sqrt (3\times3\times6)$ - 2 $\sqrt (2\times2\times6)$ - $\sqrt (4\times4\times6)$ + 4$\sqrt (3\times3\times7)$ =3$\sqrt (3^{2}\times6)$ - 2 $\sqrt (2^{2}\times6)$ - $\sqrt (4^{2}\times6)$ + 4$\sqrt (3^{2}\times7)$ =$(3\times3)$$\sqrt 6 - (2\times2)$$\sqrt 6$ - 4$\sqrt 6$ + $(4\times3)$$\sqrt 7$ 9$\sqrt 6$ - 4$\sqrt 6$ - 4$\sqrt 6$ + 12 $\sqrt 7$ (9-4-4)$\sqrt 6$ + 12 $\sqrt 7$ $\sqrt 6$ + 12 $\sqrt 7$