College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter P - Prerequisites: Fundamental Concepts of Algebra - Exercise Set P.3: 44

Answer

$\sqrt 6$ + 12 $\sqrt 7$

Work Step by Step

3$\sqrt 54$ - 2 $\sqrt 24$ - $\sqrt 96$ + 4$\sqrt 63$ =3$\sqrt (3\times3\times6)$ - 2 $\sqrt (2\times2\times6)$ - $\sqrt (4\times4\times6)$ + 4$\sqrt (3\times3\times7)$ =3$\sqrt (3^{2}\times6)$ - 2 $\sqrt (2^{2}\times6)$ - $\sqrt (4^{2}\times6)$ + 4$\sqrt (3^{2}\times7)$ =$(3\times3)$$\sqrt 6$ - $(2\times2)$$\sqrt 6$ - 4$\sqrt 6$ + $(4\times3)$$\sqrt 7$ 9$\sqrt 6$ - 4$\sqrt 6$ - 4$\sqrt 6$ + 12 $\sqrt 7$ (9-4-4)$\sqrt 6$ + 12 $\sqrt 7$ $\sqrt 6$ + 12 $\sqrt 7$
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