College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter P - Prerequisites: Fundamental Concepts of Algebra - Exercise Set P.3: 42

Answer

$-2\sqrt{3}$

Work Step by Step

$4\sqrt{12} - 2\sqrt{75}$ By the Product Rule for Square Roots $=4(\sqrt{4} \cdot \sqrt{3}) - 2(\sqrt{25} \cdot \sqrt{3})$ $=4(2 \cdot \sqrt{3}) - 2(5 \cdot \sqrt{3})$ $=8\sqrt{3} - 10\sqrt{3}$ By the Distributive Property $=(8-10)\sqrt{3}$ $=-2\sqrt{3}$
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