College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter P - Prerequisites: Fundamental Concepts of Algebra - Exercise Set P.3: 22

Answer

$3x\sqrt{2x}$

Work Step by Step

$\sqrt{6x} \cdot \sqrt{3x^{2}}$ By the product rule for square roots $=\sqrt{6x \cdot 3x^{2}}$ $=\sqrt{18x^{3}}$ $=\sqrt{9\cdot x^{2} \cdot 2 \cdot x}$ $=\sqrt{9} \cdot \sqrt{x^{2}} \cdot \sqrt{2x}$ $=3x\sqrt{2x}$
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