College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter P - Prerequisites: Fundamental Concepts of Algebra - Exercise Set P.3: 21

Answer

$2x\sqrt{3x}$

Work Step by Step

$\sqrt{2x^{2}} \cdot \sqrt{6x}$ By the product rule for square roots $=\sqrt{2x^{2} \cdot 6x}$ $=\sqrt{12x^{3}}$ $=\sqrt{4\cdot x^{2} \cdot 3 \cdot x}$ $=\sqrt{4} \cdot \sqrt{x^{2}} \cdot \sqrt{3x}$ $=2x\sqrt{3x}$
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