College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter P - Prerequisites: Fundamental Concepts of Algebra - Exercise Set P.3: 1

Answer

$6$

Work Step by Step

$\sqrt {36} = \sqrt {6^{2}} = 6$
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