College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter P - Prerequisites: Fundamental Concepts of Algebra - Exercise Set P.2: 53

Answer

$\frac{2}{b^{7}}$

Work Step by Step

Group factors with the same base: $$\frac{14b^{7}}{7b^{14}}$$ $$=(\frac{14}{7})(\frac{b^{7}}{b^{14}})$$ When dividing factors with the same non-zero base, subtract the exponent of the denominator from the exponent of the numerator: $$=2b^{(7-14)}$$ $$=2b^{(-7)}$$ Write as a fraction and move the base with the negative exponent to the other side of the fraction and make the exponent positive: $$=\frac{2}{b^{7}}$$
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