College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter P - Prerequisites: Fundamental Concepts of Algebra - Exercise Set P.2: 47

Answer

$=18x^{9}y^{5}$

Work Step by Step

When multiplying two exponential expressions, group factors with the same base: $$(-9x^{3}y)(-2x^{6}y^{4})$$ $$=(-9\times(-2))(x^{3}\times x^{6})(y\times y^{4})$$ $$=18x^{(3+6)}y^{(1+4)}$$ $$=18x^{9}y^{5}$$
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