College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter P - Prerequisites: Fundamental Concepts of Algebra - Exercise Set P.2: 46

Answer

$=99x^{17}$

Work Step by Step

When multiplying two exponential expressions, group factors with the same base: $$(11x^{5})(9x^{12})$$ $$=(11\times9)(x^{5}\times x^{12})$$ $$=99x^{(5+12)}$$ $$=99x^{17}$$
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