## College Algebra (6th Edition)

$\frac{y}{16x^{8}z^{6}}$
$$(2x^{-3}yz^{-6})(2x)^{-5}$$ When a product is raised to an exponent, raise each factor to that exponent. $$=(2x^{-3}yz^{-6})(2^{-5}x^{-5})$$ Combine like terms and simplify. $$=(2\times2^{-5})(x^{-3}\times x^{-5})(y)(z^{-6})$$ $$=(2^{(1+(-5))})(x^{-3+(-5)})(y)(z^{-6})$$ $$=(2^{-4})(x^{-8})(y)(z^{-6})$$ When an exponent is negative, write the expression as a fraction and move the base from the numerator to the denominator (or vise versa) and make the exponent positive. $$=\frac{y}{2^{4}x^{8}z^{6}}$$ $$=\frac{y}{16x^{8}z^{6}}$$