## College Algebra (6th Edition)

$5$, then $6\sqrt3$
$\sqrt3 + \sqrt {75}$ Split 75 into two factors such that one is a perfect square: $=\sqrt3 + \sqrt {25\cdot3}$ (not shown: $=\sqrt3 + \sqrt {25}\sqrt3$) $=\sqrt3 + 5\sqrt3$ (not shown: $=1\sqrt3 +5\sqrt3 = (1+5)\sqrt3$) $=6\sqrt3$