## College Algebra (6th Edition)

This problem tests how you deal with negative exponents in numerators and denominators. According to the instructions given in the textbook, When a negative number appears as an exponent,switch the position of the base (from the numerator to the denominator or from the denominator to the numerator) and make the exponent positive. The sign of the base does not change. In the given case, $\frac{1}{8^{-2}}=\frac{8^2}{1}=8^2$.