College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 6 - Matrices and Determinants - Exercise Set 6.3 - Page 624: 24

Answer

$X=\left[\begin{array}{ll} 17 & -3\\ 2 & -9\\ -7 & 16 \end{array}\right]$

Work Step by Step

$ A-X=4B\qquad$ ... add $X$ to both sides $ A=X+4B\qquad$ ... add $-4B$ to both sides $A-4B=X$ $X=A-4B$ $X=\left[\begin{array}{ll} -3 & -7\\ 2 & -9\\ 5 & 0 \end{array}\right]-4\cdot\left[\begin{array}{ll} -5 & -1\\ 0 & 0\\ 3 & -4 \end{array}\right]$ $X=\left[\begin{array}{ll} -3 & -7\\ 2 & -9\\ 5 & 0 \end{array}\right]+\left[\begin{array}{ll} 20 & 4\\ 0 & 0\\ -12 & 16 \end{array}\right]$ $X=\left[\begin{array}{ll} 17 & -3\\ 2 & -9\\ -7 & 16 \end{array}\right]$
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