College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 6 - Matrices and Determinants - Exercise Set 6.3 - Page 624: 23

Answer

$X=\left[\begin{array}{ll} 7 & 27\\ -8 & 36\\ -17 & -4 \end{array}\right]$

Work Step by Step

$ B-X=4A\qquad$ ... add $X$ to both sides $B-X+X=4A+X$ $ B=X+4A\qquad$ ... subtract $4A$ from both sides $B-4A=X$ $X=B-4A$ $X=\left[\begin{array}{ll} -5 & -1\\ 0 & 0\\ 3 & -4 \end{array}\right]-4\cdot\left[\begin{array}{ll} -3 & -7\\ 2 & -9\\ 5 & 0 \end{array}\right]$ $X=\left[\begin{array}{ll} -5-4(-3) & -1-4(-7)\\ 0-4(2) & 0-4(-9)\\ 3-4(5) & -4-4(0) \end{array}\right]$ $X=\left[\begin{array}{ll} 7 & 27\\ -8 & 36\\ -17 & -4 \end{array}\right]$
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