College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 4 - Exponential and Logarithmic Functions - Exercise Set 4.4 - Page 489: 8

Answer

$x=\frac{4}{3}$

Work Step by Step

We are given the exponential equation $5^{3x-1}=125$. We can express each side using a common base and then solve for $x$. $5^{3x-1}=5^{3}=125$ Take the natural log of both sides. $ln(5^{3x-1})=ln(5^{3})$ $(3x-1)ln(5)=3ln(5)$ Divide both sides by $ln(5)$. $3x-1=3$ Add 1 to both sides. $3x=4$ Divide both sides by 3. $x=\frac{4}{3}$
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