College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 4 - Exponential and Logarithmic Functions - Exercise Set 4.4 - Page 489: 1

Answer

$x=6$

Work Step by Step

We are given the exponential equation $2^{x}=64$. We can express each side using a common base and then solve for $x$. $2^{x}=2^{6}=64$ Take the natural log of both sides. $ln(2^{x})=ln(2^{6})$ $xln(2)=6ln(2)$ Divide both sides by $ln(2)$. $x=6$
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