College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 4 - Exponential and Logarithmic Functions - Exercise Set 4.2 - Page 467: 101

Answer

$x=10$

Work Step by Step

From the definition of the logarithmic function on page 456, we know that $y=log_{b}x$ is equivalent to $b^{y}=x$ (for $x\gt0$, $b\gt0$, and $b\ne1$). Therefore, $log_{3}(x-1)=2$ is equivalent to $3^{2}=(x-1)$ in logarithmic form. We know that $3^{2}=9$, so we can set $x-1=9$. Add 1 to both sides. $x=10$
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