College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 4 - Exponential and Logarithmic Functions - Exercise Set 4.2: 29

Answer

$\frac{1}{2}$

Work Step by Step

From the definition of the logarithmic function on page 456, we know that $y=log_{b}x$ is equivalent to $b^{y}=x$(for $x\gt0$, $b\gt0$, and $b\ne1$). Therefore, $log_{7}\sqrt 7=\frac{1}{2}$, because $7^{\frac{1}{2}}=\sqrt 7$.
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