College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 4 - Exponential and Logarithmic Functions - Exercise Set 4.2: 27



Work Step by Step

From the definition of the logarithmic function on page 456, we know that $y=log_{b}x$ is equivalent to $b^{y}=x$(for $x\gt0$, $b\gt0$, and $b\ne1$). Therefore, $log_{2}\frac{1}{8}=-3$, because $2^{-3}=\frac{1}{2^{3}}=\frac{1}{2\times2\times2}=\frac{1}{8}$.
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