College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 4 - Exponential and Logarithmic Functions - Exercise Set 4.1 - Page 454: 76

Answer

$g(x)$

Work Step by Step

$x=1990-1950=40$, $f(40)=6.25(1.029)^{40}=19.61$ $g(40)=\frac{38.8}{1+6.3e^{-0.051\times 40}} = 21.795$ The actual data on the bar graph is $21.3$. Therefore, $g(x)$ is a better model.
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