College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 1 - Equations and Inequalities - Exercise Set 1.3: 12

Answer

$x=\frac{15}{2}$

Work Step by Step

Write an equation. $y_{1}+3=y_{2}$ Substitute for $y_{1}$ and $y_{2}$. $(10x+6)+2=12x-7$ $10x+8=12x-7$ $15=2x$ $x=\frac{15}{2}$
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