College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 1 - Equations and Inequalities - Exercise Set 1.2: 27

Answer

$x=-12$

Work Step by Step

$\frac{x}{4} = 2 + \frac{x-3}{3} $ Take LCD at the right hand side $\frac{x}{4} = \frac{6+x-3}{3} $ $\frac{x}{4} = \frac{x+3}{3} $ Multiply both sides by 12 to clear fractions. $12(\frac{x}{4}) = 12(\frac{x+3}{3} )$ $3x = 4(x+3)$ $3x = 4x+12$ Combine like terms. $-12 = 4x-3x$ $-12 = x$ $x=-12$
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