College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 1 - Equations and Inequalities - Exercise Set 1.2: 16

Answer

$y=\frac{-81}{11}$

Work Step by Step

$45-[4-2y-4(y+7)]=-4(1+3y)-[4-3(y+2)-2(2y-5)]$ $45-[4-2y-4y-28]=-4-12y-[4-3y-6-4y+10]$ $45-4+2y+4y+28=-4-12y-4+3y+6+4y-10$ $6y+69=-5y-12$ (Bring pronumerals to the left and numbers to the right) $6y+5y=-12-69$ $11y=-81$ $y=\frac{-81}{11}$
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