College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 1 - Equations and Inequalities - Exercise Set 1.2: 15



Work Step by Step

$25-[2+5y-3(y+2)]=-3(2y-5)-[5(y-1)-3y+3]$ $25-[2+5y-3y-6]=-6y+15-[5y-5-3y+3]$ $25-[2y-4]=-6y+15-[2y-2]$ $25-2y+4=-6y+15-2y+2$ $-2y+29=-8y+17$ (Bring pronumerals to the left and numbers to the right) $-2y+8y=17-29$ $6y=-12$ $y=-2$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.