College Algebra (11th Edition)

Published by Pearson
ISBN 10: 0321671791
ISBN 13: 978-0-32167-179-0

Chapter R - Section R.7 - Radical Expressions - R.7 Exercises - Page 67: 44

Answer

$-\frac{\sqrt[4]{3}}{2}$

Work Step by Step

Apply the rule: $\sqrt[n]{\frac{a}{b}}=\frac{\sqrt[n]{a}}{\sqrt[n]{b}}$ $-\sqrt[4]{\frac{3}{16}}=-\frac{\sqrt[4]{3}}{\sqrt[4]{16}}$ Evaluate and simplify. $-\sqrt[4]{\frac{3}{16}}=-\frac{\sqrt[4]{3}}{2}$
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