College Algebra (11th Edition)

Published by Pearson
ISBN 10: 0321671791
ISBN 13: 978-0-32167-179-0

Chapter R - Section R.7 - Radical Expressions - R.7 Exercises - Page 67: 39

Answer

$\sqrt[3]{14xy}$

Work Step by Step

Apply the rule: $\sqrt[n]{a}\cdot\sqrt[n]{b}=\sqrt[n]{ab}$ $\sqrt[3]{7x}\cdot\sqrt[3]{2y}=\sqrt[3]{7x(2y)}$ Simplify. $\sqrt[3]{7x}\cdot\sqrt[3]{2y}=\sqrt[3]{14xy}$
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