College Algebra (11th Edition)

Published by Pearson
ISBN 10: 0321671791
ISBN 13: 978-0-32167-179-0

Chapter R - Section R.6 - Rational Exponents - R.6 Exercises - Page 57: 77

Answer

$-4k^{10/3} +24k^{4/3}$

Work Step by Step

$\begin{array}{ l l } =-4k\cdot k^{7/3} +24k\cdot k^{1/3} & \begin{array}{l} \mathrm{Apply\ the\ distributive\ property}\\ a( b+c) =ab+ac \end{array}\\ & \\ =-4k^{3/3+7/3} +24k^{3/3+1/3} & \begin{array}{l} \mathrm{Apply\ the\ rule}\\ a^{b} \cdot a^{c} =a^{b+c} \end{array}\\ & \\ =-4k^{10/3} +24k^{4/3} & \mathrm{Add\ fractions\ to\ simplify} \end{array}$
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