College Algebra (11th Edition)

Published by Pearson
ISBN 10: 0321671791
ISBN 13: 978-0-32167-179-0

Chapter R - Section R.5 - Rational Expressions - R.5 Exercises - Page 47: 32

Answer

$\dfrac{x-4}{x-5}$

Work Step by Step

The given expression, $ \dfrac{x^2+2x-15}{x^2+11x+30}\cdot\dfrac{x^2+2x-24}{x^2-8x+15} ,$ simplifies to \begin{array}{l}\require{cancel} \dfrac{(x+5)(x-3)}{(x+5)(x+6)}\cdot\dfrac{(x+6)(x-4)}{(x-3)(x-5)} \\\\= \dfrac{(\cancel{x+5})(\cancel{x-3})}{(\cancel{x+5})(\cancel{x+6})}\cdot\dfrac{(\cancel{x+6})(x-4)}{(\cancel{x-3})(x-5)} \\\\= \dfrac{x-4}{x-5} .\end{array}
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.