College Algebra (11th Edition)

Published by Pearson
ISBN 10: 0321671791
ISBN 13: 978-0-32167-179-0

Chapter R - Section R.4 - Factoring Polynomials - R.4 Exercises - Page 40: 93

Answer

$(10x+7y)(100x^2-70xy+49y^2)$

Work Step by Step

Using $a^3\pm b^3=(a\pm b)(a^2\mp ab+b^2)$ or the factoring of two cubes, the factored form of the given expression, $ 1000x^3+343y^3 ,$ is \begin{array}{l}\require{cancel} (10x+7y)[(10x)^2-10x(7y)+(7y)^2] \\\\= (10x+7y)(100x^2-70xy+49y^2) .\end{array}
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