College Algebra (11th Edition)

Published by Pearson
ISBN 10: 0321671791
ISBN 13: 978-0-32167-179-0

Chapter R - Section R.4 - Factoring Polynomials - R.4 Exercises: 70

Answer

(5 - 4a + b)(16$a^{2}$ + $b^{2}$- 8ab + 20a - 5b + 25)

Work Step by Step

125 - $(4a - b)^{3}$ is a difference of cubes, so we write it as a difference of cubes and factor: $5^{3}$ - $(4a - b)^{3}$ = (5 - (4a - b))($5^{2}$ + 5(4a - b) + $(4a - b)^{2}$) = (5 - 4a + b)(25 + 20a - 5b + 16$a^{2}$ - 8ab + $b^{2}$) = (5 - 4a + b)(16$a^{2}$ + $b^{2}$- 8ab + 20a - 5b + 25)
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