College Algebra (11th Edition)

Published by Pearson
ISBN 10: 0321671791
ISBN 13: 978-0-32167-179-0

Chapter R - Section R.4 - Factoring Polynomials - R.4 Exercises: 67

Answer

r($r^{2}$ + 18r + 108)

Work Step by Step

$(r + 6)^{3}$ - 216 is a difference of cubes, so we write it as a diference of cubes and factor: $(r + 6)^{3}$ - $6^{3}$ = (r + 6 - 6)($(r + 6)^{2}$ + (r + 6)(6) + $6^{2}$) = r($r^{2}$ + 12r + 36 + 6r + 36 + 36) = r($r^{2}$ + 18r + 108)
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