College Algebra (11th Edition)

Published by Pearson
ISBN 10: 0321671791
ISBN 13: 978-0-32167-179-0

Chapter R - Section R.4 - Factoring Polynomials - R.4 Exercises: 63

Answer

(5x - 3)(25$x^{2}$ + 15x + 9)

Work Step by Step

125$x^{3}$ - 27 is a difference of cubes, so we write it as a difference of cubes and factor: $(5x)^{3}$ - $3^{2}$ = (5x - 3)($(5x)^{2}$ + 5x(3) + $3^{2}$) = (5x - 3)(25$x^{2}$ + 15x + 9)
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