College Algebra (11th Edition)

Published by Pearson
ISBN 10: 0321671791
ISBN 13: 978-0-32167-179-0

Chapter R - Section R.4 - Factoring Polynomials - R.4 Exercises: 62

Answer

(3 - r)(9 + 3r + $r^{2}$)

Work Step by Step

27 - $r^{3}$ is a difference of cubes, so we write it as a difference of cubes and factor: $3^{3}$ - $r^{3}$ (3 - r)($3^{2}$ + 3r + $r^{2}$) = (3 - r)(9 + 3r + $r^{2}$)
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