College Algebra (11th Edition)

Published by Pearson
ISBN 10: 0321671791
ISBN 13: 978-0-32167-179-0

Chapter R - Section R.4 - Factoring Polynomials - R.4 Exercises: 58

Answer

(p - 2q + 10)(p - 2q - 10)

Work Step by Step

We know that (a + b)(a - b) = $a^{2}$ - $b^{2}$, so we take the square root of each term in the polynomial to get a and b. We get (p - 2q) and 10, so the factorization is ((p - 2q) + 10)((p - 2q) - 10) = (p - 2q + 10)(p - 2q - 10)
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