## College Algebra (11th Edition)

Published by Pearson

# Chapter R - Section R.4 - Factoring Polynomials - R.4 Exercises: 56

#### Answer

(6z + 9$y^{2}$)(6z - 9$y^{2}$)

#### Work Step by Step

We know that (a + b)(a - b) = $a^{2}$ - $b^{2}$, so we take the square root of each term in the polynomial to get a and b. We get 6z and 9$y^{2}$, so the factorization is (6z + 9$y^{2}$)(6z - 9$y^{2}$).

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