## College Algebra (11th Edition)

Published by Pearson

# Chapter R - Section R.4 - Factoring Polynomials - R.4 Exercises: 15

#### Answer

(m - 1)(2$m^{2}$ - 7m + 5)

#### Work Step by Step

1. The GCF of 2(m - 1), -3$(m - 1)^{2}$, and 2$(m - 1)^{3}$ is (m - 1). 2. Factor out the GCF. (m - 1)(2 - 3(m - 1) + 2$(m - 1)^{2}$) 3. Simplify expression in parentheses. (m - 1)(2 - 3(m - 1) + 2($m^{2}$ - 2m + 1)) = (m - 1)(2 - 3m + 1 + 2$m^{2}$ - 4m + 2) = (m - 1)(2$m^{2}$ - 7m + 5)

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