College Algebra (11th Edition)

Published by Pearson
ISBN 10: 0321671791
ISBN 13: 978-0-32167-179-0

Chapter R - Section R.3 - Polynomials - R.3 Exercises - Page 30: 96

Answer

$3,591$

Work Step by Step

$\bf{\text{Solution Outline:}}$ To simplify the given expression, $ 63\times57 ,$ get the middle number between $63$ and $57$. Then use the special product for the sum and difference of like terms. $\bf{\text{Solution Details:}}$ The middle number between $63$ and $57$ is $60.$ Using the product of the sum and difference of like terms which is given by $(a+b)(a-b)=a^2-b^2,$ the expression above is equivalent\begin{array}{l}\require{cancel} (60+3)(60-3) \\\\= (60)^2-(3)^2 \\\\= 3600-9 \\\\= 3,591 .\end{array}
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