College Algebra (11th Edition)

Published by Pearson
ISBN 10: 0321671791
ISBN 13: 978-0-32167-179-0

Chapter R - Section R.3 - Polynomials - R.3 Exercises: 73

Answer

$y^3+6y^2+12y+8$

Work Step by Step

Using $(a\pm b)^3=a^3\pm3a^2b+3ab^2\pm b^3$ or the cube of a binomial, the expression, $ (y+2)^3 ,$ is equivalent to \begin{array}{l}\require{cancel} (y)^3+3(y)^2(2)+3(y)(2)^2+(2)^3 \\\\= y^3+3(y^2)(2)+3(y)(4)+8 \\\\= y^3+6y^2+12y+8 .\end{array}
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