College Algebra (11th Edition)

Published by Pearson
ISBN 10: 0321671791
ISBN 13: 978-0-32167-179-0

Chapter R - Section R.3 - Polynomials - R.3 Exercises - Page 30: 72

Answer

$4m^2+28m+49-4mn-14n+n^2$

Work Step by Step

Using $(a\pm b)^2=a^2\pm2ab+b^2$ or the square of a binomial, the expression, $ [(2m+7)-n]^2 ,$ is equivalent to \begin{array}{l}\require{cancel} (2m+7)^2-2(2m+7)(n)+(n)^2 \\\\= (2m+7)^2-4mn-14n+n^2 \\\\= (2m)^2+2(2m)(7)+(7)^2-4mn-14n+n^2 \\\\= 4m^2+28m+49-4mn-14n+n^2 .\end{array}
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