College Algebra (11th Edition)

Published by Pearson
ISBN 10: 0321671791
ISBN 13: 978-0-32167-179-0

Chapter R - Review Exercises - Page 75: 50

Answer

$\dfrac{26}{5}$

Work Step by Step

Substituting $a=-1$, $b=-2$, and $c=4$, the given expression, $ (a-2)\div5\cdot b+c ,$ evaluates to \begin{array}{l}\require{cancel} (-1-2)\div5\cdot (-2)+4 \\\\= (-3)\div5\cdot (-2)+4 \\\\= -\dfrac{3}{5}\cdot (-2)+4 \\\\= \dfrac{6}{5}+4 \\\\= \dfrac{6}{5}+\dfrac{20}{5} \\\\= \dfrac{26}{5} .\end{array}
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