College Algebra (11th Edition)

Published by Pearson
ISBN 10: 0321671791
ISBN 13: 978-0-32167-179-0

Chapter 5 - Section 5.1 - Systems of Linear Equations - 5.1 Exercises - Page 486: 15

Answer

$x = 3, y = -4$

Work Step by Step

Solving for $x$ in $-2x = 6y + 18 $ gives $x = -3y - 9$ Plug this into the $x$ in $-29 = 5y - 3x$ to obtain: $-29 = 5y - 3(-3y - 9 ) \\-29 = 5y + 9y + 27 \\-56 = 14y \\y = -4$ Plug $-4$ to the $y$ in $x = -3y - 9$ to obtain: $x = -3(-4) - 9 \\x=12-9 \\x= 3$
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