College Algebra (11th Edition)

Published by Pearson
ISBN 10: 0321671791
ISBN 13: 978-0-32167-179-0

Chapter 4 - Section 4.5 - Exponential and Logarithmic Equations - 4.5 Exercises - Page 446: 25

Answer

$x\approx25.6765$

Work Step by Step

Given Expression $2(1.05)^x+3=10$ Subtract 3 from both sides. $2(1.05)^x=7$ Divide both sides by 2. $(1.05)^x=\frac{7}{2}$ Take log of both sides. $\log(1.05)^x=\log\frac{7}{2}$ Power Rule of logarithms. $x\log1.05=\log\frac{7}{2}$ Solve for $x$. $x=\frac{\log\frac{7}{2}}{\log1.05}$ $x\approx25.6765$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.