College Algebra (11th Edition)

Published by Pearson
ISBN 10: 0321671791
ISBN 13: 978-0-32167-179-0

Chapter 4 - Section 4.5 - Exponential and Logarithmic Equations - 4.5 Exercises - Page 446: 22

Answer

$x\approx6.5788$

Work Step by Step

Given expression $1.2(.9)^x=6$ Divide both sides by 1.2. $(.9)^x=0.5$ Take log of both sides. $\log(.9)^x=\log0.5$ Use the Power Rule of logarithms. $x\log0.9=\log0.5$ Solve for $x$. $x=\frac{\log0.5}{\log0.9}$ $x\approx6.5788$
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