College Algebra (11th Edition)

Published by Pearson
ISBN 10: 0321671791
ISBN 13: 978-0-32167-179-0

Chapter 4 - Section 4.5 - Exponential and Logarithmic Equations - 4.5 Exercises - Page 446: 15

Answer

$x=\pm2.146$

Work Step by Step

Given Expression $e^{x^2}=100$ Take natural log of both sides. $\ln{e^{x^2}}=\ln100$ Use the definition of a natural log and Power Rule of logarithms. $x^2=\ln100$ Solve for $x$. $x=\pm\sqrt{\ln100}$ $x=\pm2.146$
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